-0.0001x^2+0.06x-1.5=0

Solution for -0.0001x^2+0.06x-1.5=0 equation:

-0.0001x^2+0.06x-1.5=0

a = -0.0001; b = 0.06; c = -1.5;
Δ = b2-4ac
Δ = 0.062-4·(-0.0001)·(-1.5)
Δ = 0.003
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.06)-\sqrt{0.003}}{2*-0.0001}=\frac{-0.06-\sqrt{0.003}}{-0.0002}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.06)+\sqrt{0.003}}{2*-0.0001}=\frac{-0.06+\sqrt{0.003}}{-0.0002}
$